We use Cookies to give you best experience on our website. By using our website and services, you expressly agree to the placement of our performance, functionality and advertising cookies. Please see our Privacy Policy for more information. Abstract: No abstract text available Text: e r at m a xim u m a ccess tim e s as fast as 35ns. Abstract: No abstract text available Text: sur les condensateurs ceramique haute tem perature classe 2 p. S tand by: 5m W typ.

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By using our site, you acknowledge that you have read and understand our Cookie Policy , Privacy Policy , and our Terms of Service. Electrical Engineering Stack Exchange is a question and answer site for electronics and electrical engineering professionals, students, and enthusiasts. It only takes a minute to sign up. If this is total consumption for both supply pins , can I except that the transducer is going to draw equally on each supply pin, i. All of these devices work using Hall-effect sensors.

This is represented in the schematic by the X-box. Figure 2. Source: Power Guru. The amplifier runs a current through the coil winding so that the flux in the core sums to zero. This is rather clever as it removes all non-linearities of the core from the performance of the device. It is never driven into saturation if operated within spec and never leaves zero so there are no hysteresis effects either.

The flux cancelling current is fed to the output and will be directly proportional to the primary current. You might want to re-phrase the question. The power will be consumed by the transducer and the load RM. Worst case for the transducer will be with maximum current and voltage drop into minimum RM. Probably not. The datasheet is not very comprehensive so I am guessing a bit.

If it's important: measure! And next to that it will draw I s from the supply "in general". If I s flows out of the device it will be drawn from the positive supply and vv. Together mW. Note that this is the worst case possible, where you continuously measure 50A DC. If you measure sine-shaped or small currents, I s will on average be smaller, and so the average power will drop.

In that case you will need to find the rms value of the current you measure to determine the average power you will need for driving I s. Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. Asked 3 years, 8 months ago.

Active 3 years, 8 months ago. Viewed 1k times. Thanks, M. Marko Gulin Marko Gulin 1, 2 2 gold badges 7 7 silver badges 29 29 bronze badges. Active Oldest Votes. What is the total power consumption of the transducer? Transistor Transistor k 9 9 gold badges silver badges bronze badges. I suspect you only care about your power budget in which case your analysis is correct.

Thank you for clarifications, this is really helpful! The device itself needs 10mA continuously from both supply rails to work. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. The Overflow Blog. Podcast JavaScript is ready to get its own place. Featured on Meta. What posts should be escalated to staff using [status-review], and how do I….

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LA55P 50a. Datasheet pdf. Equivalent



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